If a base angle of an isosceles triangle is 16 degrees more than half of the measure of its vertex angle, then the vertex angle is ? Degrees. Show your work

Question

Practice problem I’m very confused on. Please help me!

Answer 1

An isosceles triangle has 2 angles that are equal

all 3 sum to 180

2x + y+ 180

x=16+y/2

2x = 32 +y

2x = 180-y

subtract 2nd to last equation above from the last to get

0 = 148-2y

2y = 148

y= 148/2 = 74

2x = 32 + 74 = 106

x = 106/2 = 53

53+ 53 + 74 = 180

base angles are 53 and 53 degrees

apex angle is 74 degrees

Answer 2

v represents the vertex angle

(v/2) + 16 represents a base angle

v + (v/2) + 16 + (v/2) + 16 = 180

2v + 32 = 180

2v = 148

v = 74