You can’t use a double-angle formula here (since - 13π/12 isn’t twice any angle whose trig values we know offhand), but we can use the difference formula for sinx. We need to find two “friendly” angles whose difference is - 13π/12, so π/4 and 4π/3 will suit our needs well.
sin(-13π/12) = sin(π/4 - 4π/3)
Now we use the difference formula: sin(π/4 - 4π/3) = sin(π/4)⋅cos(4π/3) - sin(4π/3)⋅cos(π/4)
= (√2/2)⋅(- 1/2) - (√3/2)⋅(√2/2) = - √2/4 - √6/4
Zhan Y.
hi thank you but this is a similar problem and its answer can you please take a look at it ? Recall: when using the double angle formulas, we want to use special angles since we know how to find their exact values. For this type of question, we will use the double angle formula for cosine because we can choose an identity that is in terms of sine alone (the double angle formula for sine has both sine and cosine in it). The double angle formula for sine has both sine and cosine in it (i.e. sin2x = 2sinxcosx), so that would complicate the problem further. So, cos2 (5π / 8) = cos (5π/4) LS: choose the double angle formula for cosine that has only sine RS: cos(5π/4) is in Q3, use unit circle or special triangles for the exact value. 1 − 2sin^2 (5π/8) = −1/√2 The rest is just isolating sin (5π/8) −2sin^2 (5π/8) = −1/√2 / −√2/√2 -subtract one from the RS (common deno) sin^2 (5π/8) = −1/−√2 / −2√2 = −(1+√2) / −2√2 - divide both sides by -2. √sin^2 (5π/8) = ±√(big)1+√2 / 2√2 - take the square root of both sides11/26/20