Jessica H. answered 11/24/20
Graduated university student who can tutor/mentor in Geometry
The answer is 85 rides.
Solution:
Admission fee is only paid once upon entry to the fair.
This means you subtract $5 from the total $175.
($175 - $5) = $170 leftover money that Daniel has.
Since the given statement said all the rides cost $2 each,
we can safely assume that all the rides cost the same.
To figure out what the greatest number of rides Daniel can go on,
we simply divide $170 by $2 to get the maximum number of rides he can go on.
170/2 = 85 rides