Jon S. answered 11/24/20
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kth term of a binomial expansion. r = k - 1. C(n,r) x^(n-r)y^r, where CC(n,r) is number of combinations of n taken r at a time
here n = 35 and r = 9 - 1 = 8, so
9th term is C(35,8)x^27y^8