If I understand this problem correctly, ant A is 1m from a wall which is 4m in height. Ant B is somewhere on the wall. The line of sight from ant A to ant B is an angle of 62o. The triangle formed here is a right triangle with an hypotenuse c.
If this understanding is correct, then the place on the wall where ant B is located will be given by tangent 62o = 1m ÷ c; 0.46947 = 1m ÷ c
The hypotenuse c equals 1m ÷ 0.46947 = 2.13m
So, ant B is too far away to hear the call from ant A