Logarithm Algebra

Question

ln2 = a

ln7 = b

Using the properties of logarithms write this log in terms of a and b

logarithm = ln$\sqrt[3]{1}4$

Answer 1

ln14 = ln2 + ln7 = a+b

ln14^1/3 = (1/3)ln14 = (1/3)(a + b) = (a+b)/3