thermochemistry problem (please help if u can!)

Question

When 0.467 g of sodium metal is added to an excess of hydrochloric acid, 4950 J of heat are produced. What is the enthalpy of the reaction as written?

2Na (s) + 2 HCL (aq) → 2NaCL (aq) + H₂ (g)

Answer 1

2Na (s) + 2 HCL (aq) → 2NaCL (aq) + H₂ (g) ... balanced equation

Since we have an excess of HCl, we can base our calculations on the amount of sodium present.

moles Na present = 0.467 g Na x 1 mol Na/23.0 g = 0.0203 moles Na

4950 J / 2 mol Na x 0.0203 mol Na = 101 J = enthalpy of reaction as written