J.R. S. answered 11/21/20
Ph.D. University Professor with 10+ years Tutoring Experience
(a) q = mC∆T where q = heat = ?; m = mass of water = 200.0 g; C = sp.heat = 4.184 J/gº; ∆T = change in temperature = 10.0º
q = (200.0 g)(4.184 J/gº)(10) = 8368 J
(b) Combustion of ethanol: C2H5OH + 3O2 ==> 2CO2 + 3H2O ... balanced equation
mol C2H5OH needed to generate 8368:
8368 J x 1 kJ/1000 J x 1 mol C2H5OH / 1368 kJ = 0.006117 moles
millimoles ethanol = 6.12 millimoles
(c) 0.006117 moles ethanol x 46.07 g/mol = 0.2818 g ethanol
0.2818 g x 1 ml/0.78 g = 0.361 ml