Write an equation in slope intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation

Question

(-1,-6), x+3y=6

Answer 1

3y=-x + 6

y = (-1/3)x + 2

a perpendicular line will have slope = 3, the negative inverse of -1/3

y=3x + b, to find b plug in the point (-1,-6) to get

-6 = 3(-1) + b

b = -3

the perpendicular line through the point (-1,-6) is

y=3x -3