Hi Sandra
y = -x - 5
Give the equation of the line that passes through (-3,-2) and is Perpendiculat to
y=x+2
The line above is in Slope Intercept Form
The Slope, m = 1
A perpendicular would a negative inverse Slope and that would b -1
Your Perpendicular Line starts as
y = -x + b
Use the coordinates of the point on the perpendicular, given (-3.-2) to find b
-2 = -(-3) + b
-2 = 3 + b
Subtract 3 from both sides of the equation
-2 - 3 = b
-5 = b
And your Perpendicular Line is
y = -x - 5
You can graph both lines at Desmos.com to see that they are Perpendicular and the Perpendicular passes through (-3,-2)
I hope this helps
