Knowing that ∆Hvap for water is 40.7 kJ/mol, calculate Pvap of water at 37°C

Question

I had gotten the answer 6.90 torr, but the correct one says ita 52.6 torr.. Confused about what I had done wrong!

Answer 1

Did you use the Clausius-Clapeyron equation?

ln(P1/P2) = ∆Hvap/R (1/T2 - 1/T1)

P1 = 760 torr

P2 = ?

∆Hvap = 40.7 kJ/mol

R = 8.314 J/Kmol = 0.008314 kJ/Kmol

T1 = 298K

T2 = 310K

... and solve for P2 in torr