Write the complex number in polar form 2-2 sqrt(3i)

Question

Please show steps to solve, thank you.

Answer 1

I assume your number is 2-2isqrt(3) or a = 2, b= -2sqrt(3)

r is sqrt(a^2 + b^2)

theta = inv tan (b/a). because a is positive, the theta with be correct. You may have to add 2pi to your negative answer if theta is supposed to go from 0 to 2pi .