Mirian C. answered 11/15/20
I have 8+ years of experience tutoring math; would love to help you!
Does the problem not state how many total frames she bought?
Just by trial and error I get that she bought 7 of the big frames that cost $14 and 13 of the small frames that cost $4.
The process should be
X+Y=T <----Eq(1)
Where,
X=number of big frames bought
Y=number of small frames bought
T= total of number of frames bought
Where T is given:
14X+4Y=150(T) <-----Eq(2)
Then you can solve Eq(1) for either in terms of X or Y and plug into Eq(2):
You will get the number of frames for either X or Y depending which you solved for then plug that into Eq(1) to solve for the number of frames of the other.