
Reinaldo G. answered 11/13/20
Experience teacher of Precalculus
When the remainder of the division equals zero, it is proof that the divisor is a factor of the dividend.
Given p(x) = 2x3 - 3x2 - 11x - 20 and k = 4:
4 | 2 -3 -11 -20 given
4 | 2 -3 -11 -20 lower the 2
2
4 | 2 -3 -11 -20 multiply 4 * 2 = 8; -3 + 8 = 5
8
2 5
4 | 2 -3 -11 -20 multiply 4 * 5 = 20; -11 + 20 = 9
8 20
2 5 9
4 | 2 -3 -11 -20 multiply 4 * 9 = 36; -20 + 36 = 16
8 20 36
2 5 9 16
p(k) = p(4) = 16, according to the Remainder Theorem
Since the remainder is not equal zero, then k = 4 is not a zero of the polynomial.