
Jennifer B. answered 11/12/20
Experienced teacher and tutor specializing in math and physics.
Newton's second law: F = ma
Definition of acceleration: a = (v - vo)/t
m = 0.06 kg
t = 0.05 s
v = 45 m/s
vo = 0
Θ = 40o
Part a) we are given the mass, change in velocity, and time the club was in contact with the ball. The force of the club:
F = ma
F = m (v-vo)/t
= (0.06kg)(45m/s)/0.05s)
= (0.06)(45)/0.05 kg*m/s2.(Newton)
b) The time the ball is in the air is only affected by gravitational acceleration, thus use only the 'y direction' to determine time of flight. Remember total time = tup + tdown . Since there isn't any air resistance, tup = tdown . Solve for tup using kinematic equations. Hint: what is vfinal for the trip 'up'? *** use only the 'y' component of the initial velocity *** Use a triangle and trig relations with the velocity vector on the diagonal at an angle of 400 with the horizontal to find vy - the vertical component- (and vx - the horizontal component- for part d) . Use only sine and cosine.
c) Given that the flagstick is 238 m away from the initial position of the ball, we need to calculate the total distance in the 'x direction' for the horizontal distance traveled by the golf ball. Using total time and vx from above, and the definition of velocity (v = d/t), we can determine the distance traveled (d = v*t) . Compare it to the distance given for the flagstick before the initial hit to determine where the ball landed with respect to the flagstick.
d) To determine the height the ball travels, we need the time calculated from part b. Only the time going up since we want total height. Use that with the other information and the kinematic equations to solve for height. (Using tup from part a and vy from part b.)