what is the equation for the line that is perpendicular to y=1/10x-19.5 and passed through the point (-30,15)

Answer 1

Our line will have an equation y=Ax+B. Since we want the two lines to be perpendicular we must have that A(1/10)=-1 or A=-10. To find B we solve the equation 15=(-10)(-30)+B or B=-285. So our line is given by the equation y=(-10)x-285.