What is the equation in slope-intercept form of the line that passes through the point (2, -2) and is PERPENDICULAR to the line represented by y = 2/5x + 2? *

Answer 1

y+2 = (-5/2)(x-2)

just plug in the negative inverse of 2/5 as the slope of the perpendicular, m=-5/2 and the point (2,-2) as (h,k) in the point slope formula. h=2, k=-2

y - k = m(x-h)

Answer 2

A perpendicular line to the given line will have a slope of -1/m or -5/2 in this case.

y-y₁ = m(x-x₁) --> y-(-2) = -5/2(x-2) --> y+2 = -5x/2 + 5

y = -5x/2 + 3