Find two consecutive integers such that the larger is nine more than twice the smaller

Answer 1

Consecutive means that these integers are only one apart - we could represent them as x and x+1. We know we are looking for a value of x such that the larger (x+1) is equal to 9 more than 2 times the smaller (x). We could represent this in equation form by x+1 = 2x+9. From here you just need to solve for x and then plug into x and x+1 to get your integers.

Answer 2

X+1=2x+9

1=x+9

X=-8