Write an equation in slope-intercept form of the line with a slope of −3 4 and y-intercept of –5.

Answer 1

We want to find the equation of a line using slope-intercept form therefore lets look at the equation for slope-intercept form: y = m * x + b

Now y is the y-coordinate, x is the x-coordinate, m is the slope and b is the y intercept. Now lets look at what is given to us: slope is -3 4 and y-intercept of -5. Therefore we have b, b= -5, and will need to calculate m. Now to calculate slope you use the equation of rise over run which is the shift in the y-coordinate direction divided by the shift in the x-coordinate direction. Now I am not sure if the question is stating -3 is the run and 4 is the rise or if it is coordinates (-3,4).

If it is the first case then it is simply 4 / -3 = -4/3 = m

If it is the second case then we use the second coordinates that is given (0,-5) to calculate the slope with the equation :

(y2 - y1) / (x2 - x1)

It doesn't matter which set of coordinates you use are y1 or y2 as long as you make sure to use the correspond x value:

(4 - -5) / (-3 - 0) = 9 / -3 = -3

Answer 2

slope intercept form is y=mx + b, where m is the slope of the line and b is the y-intercept.

we are given that the slope m = -3/4 and the y-intercept b = -5, so plugging those values into the equation:

y = (-3/4) - 5

Answer 3

y= (-3/4)x -5

general equation is

y= mx +b where m=slope and b= y intercept

just plug in m= -3/4 and b = -5 to get

y= (-3/4)x -5

or eliminate the fraction to get

4y = -3x -5

maybe eliminate one negative sign to get

3x + 4y = -5

or eliminate that last negative sign to get

3x + 4y + 5 = 0