Find four consecutive integers such the twice the sum of the first and third is 26 less than 5 times the fourth

Question

I have another- sorry. Find three consecutive even integers such that 11 more than twice the largest is 9 more than the smallest

Answer 1

x, x+1, x+2, x+3 are 4 consecutive integers

2(x + x+2) = 5(x+3) - 26

2(2x+2) = 5(x+3) - 26

4x + 4 = 5x + 15 - 26

4x + 4 = 5x - 11

15 = x

15, 16, 17, 18

x, x+2, x+4 consecutive even integers

2(x+4)+11 = x + 9

2x + 8 + 11 = x + 9

2x + 19 = x + 9

x = -10

-10, -8, -6