Hello, Nylah,
We want an equation that tells us how many gallons of water are in the bathtub as a function of time. The water is filling at a constant rate, so the equation should resemble a straight line. A good start is the familiar y = mx + b equation for a straight line, and think about what each term means. Let's assign the following:
y is the gallons of water in the bathtub.
x is the time, in minutes
m, the slope of the line, will be the rate water enters the tub (2 gallons/minute).
and b will be the starting point (there are 6 gallons already in the tub).
let's try putting these numbers into the equation and see if it makes sense.
y = 2(gal/min)*x + 6(gal)
It works for t = 0 min, since y = 6 gallons, where we started.
After 1 minute, we would expect to have 8 gallons, and the equation predicts that, since y = 2(gal/min)*1 min + 6(gal) = 8 gallons.
You can check other points to be certain this is correct. y = 2x + 6 will predict the number of gallons in the tub after x minutes (where x => 0).
To find how many minutes it takes for 38 gallons, enter the 38 for y and solve for x.
38 = 2x + 6
32 = 2X
x = 16 minutes.
I hope this helps.
Bob
Nylah T.
Thank you! Can you also answer my other two questions.11/05/20