Forces of Friction- Physics

Question

A little girl pulls a 5.0 kg wagon with her 15.0 kg brother along the level ground in a straight path. She exerts a force of 60.0 N on the wagon at an angle of 30 degrees above the horizontal. The coefficient of

friction between the wagon and the ground is 0.10

a) How should I calculate the normal force of the ground acting on the wagon

b) How should I calculate the acceleration of the cart with the boy in it?

Answer 1

a) N is normal force: N = mg - Fsinθ = 20kg·9.8m/s² - 60Nsin30° = 166 N. (20kg this total mass wagon and boy);

b) Fcosθ - μN = ma; a = (60Ncos30° - 0.10·166N)/20kg = 1.7681 m/s²