Inactive Tutor answered 11/04/20
Tutor
New to Wyzant
f(x) = ax2 + 20
f(30 = 0
a(30)2 + 20 = 0
90a = -20
a = -2/9
f(x) = (-2/9)x2 + 20
f(10) = ?
Jordan M.
asked 11/04/20an arch is in the shape of a parabola. If the arch is 60M across at it's base and 20M high in the middle, how high would the arch be 10M from the middle?
Inactive Tutor answered 11/04/20
f(x) = ax2 + 20
f(30 = 0
a(30)2 + 20 = 0
90a = -20
a = -2/9
f(x) = (-2/9)x2 + 20
f(10) = ?
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