
Patrick B. answered 11/04/20
Math and computer tutor/teacher
The demand line is required...
the slope of the demand line is -100 = -100/$1 as given
Also given is ($8,2000)
B = y - mx = 2000 - (-100)(8)
= 2000 + 800
= 2800
D(p) = -100p+2800 is the equation of the demand line
The revenue function is
R(p) = p(-100p+2800)
= -100p^2 + 2800p
Maximizing:
0 = dR/dp = -200p + 2800
-2800/-200 = pMax
p = 14