What is the equation of a line that is perpendicular to y=-7/2x+1 and goes through (14,3)

Answer 1

y = (-7/2)x + 1 is what mark is trying to say...

Other software can mistake it for -7/(2x) +1 or

even y = -7/(2x+1) where the x is in the denominator

the slope of the perpendicular line is 2/7

B = y - mx

= 3 - (2/7)(14)

= 3 - 4

= -1

y = (2/7)x - 1