Find the 3rd term of the expansion (2x + 2y)^10

Question

explain the steps please :)

Answer 1

for (x+y)^n, kth term of a binomial expansion. r = k-1., C(n,r)x^(n-r)y^r

here x = 2x

y = 2y

n = 10

k = 3

r = 2

C(10,2)(2x)^8(2y)^2

45*2^10*x^8y^2

46080x^8y^2