Patrick B. answered 11/03/20
Math and computer tutor/teacher
3y = -2x
y = (-2/3)x
The parallel line must also have slope -2/3
B = y - mx= 2 - (-2/3)(3) = 2 - -2 = 4
y = (-2/3)x + 4
Murray B.
asked 11/03/20Write the slope-intercept form of an equation of the line that passes through the given point and is parallel to the line of the equation shown. (3,2) 3y=-2x
Patrick B. answered 11/03/20
Math and computer tutor/teacher
3y = -2x
y = (-2/3)x
The parallel line must also have slope -2/3
B = y - mx= 2 - (-2/3)(3) = 2 - -2 = 4
y = (-2/3)x + 4
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