Raymond B. answered 11/03/20
Math, microeconomics or criminal justice
let 2 feet width = 24 inches
the the sides of the box are
V = x(24-2x)^2 where x is the side of the cut out square of each corner
expand, take the derivative, set = 0 and solve for x
4x^3 -24 x^2 + 144
V' = 3x^2 - 48x + 144 =0
x^2 -16x +46 = 0
x = 8-4.2 = 3.8 inches = close to 1/3 foot
largest volume is about 3.8(24-7.6)^2 cubic inches
or roughly 1/3 ft by 4/3 ft by 4/3 ft = about 16/27 cubic feet