The perimeter of a triangle is 70. If the length of the second side is twice the first side and the length of the third side is 22 more than the first side , then find the length of the first side .

Answer 1

Hi Dj F

For your triangle the perimeter, P = 70 the sum of all three sides let

x = first side

2x = second side

x + 22 = third side

Based on the information given

Since the perimeter, P, is the sum of all the sides then

x + 2x + x + 22 = 70

Combine like terms

4x + 22 = 70

Subtract 22 from both side of the equation

4x = 48

Divide both sides by 4

x = 12 the first side

Make the substitutions based on the given information above

2x = 24 the second side

x + 22 = 34 the third side

Checking

12 + 24 + 34 = 70

70 = 70

I hope this helps