A=4, B=2, c=6, d=-8: ab+ a(cd - ab - 4^2) + ac(d/a - bc/a +2^3)

Question

The letters before the colon are A math key to show what each letters value is

Answer 1

A=4, B=2, c=6, d=-8: ab+ a(cd - ab - 4^2) + ac(d/a - bc/a +2^3)

Hey Jayden! I see you have a problem with variables and you're tryna solve for an expression here. So the first thing you'd want to do is substitute those values for the numbers, so you'd have:

4*2 + 4(6*(-8) - 4*2 - 4^2) + 4*6(-8/4 - 2*6/4 + 2^3)

Now we have to remember to use order of operations (PEMDAS), so the first thing we look for is parenthesis. And we have some numbers in the parenthesis, but we need to solve them in order to progress further. So in the parenthesis, we have to solve for exponents (E) first, so you'll have:

4*2 + 4(6*(-8) - 4*2 - 16) + 4*6(-8/4 - 2*6/4 + 8)

We solved 4^2 which is 16 and 2^3 which is 8. Next we have multiplication (M) and division (D), so we do as follows:

4*2 + 4(-48 - 8 - 16) + 4*6(-2 - 3 + 8)

We solved -8/4 which was -2, 6*(-8) which was -48, 2*6/4 which was 2*6 giving you 12, divided by 4 which is 3. Now we have A/S which is addition and subtraction:

4*2 + 4(-72) + 4*6(3)

We solved (-48-4-16) which is -72, and (-2-3+8) which is 5. We finished everything in the parenthesis, so we can backtrack to E in the general form (Exponents) since we finished P (Parenthesis), but we have no exponents, so we go to M (Multiplication)

8 - 288 + 72

We solved for 4*2 which is 8, 4(-72) which is -288, and 4*6(3) where 4*6 is 24 and 24(3) is 72:

Now we can add everything together to get:

-208

Answer 2

answer = -208

remember PEMDAS

parenthesis first

exponent: 4^2=16

cd=-48

ab=8

(-48-8-16)=-72

4(-72)=-288

exponent: 2^3=8

d/a=-2

bc=12

bc/a=3

(-2-3+8)=3

ac=24

24(3)=72

ab=8

8-288+72=-208