Patrick B. answered 10/26/20
Math and computer tutor/teacher
x-1 < 4
x< 5
open circle at 5, shades to the left
Note that for x=5, the borderline condition
behaves as expected, 5-1<4 --> 4<4 is technically false
for x=0 --> 0-1 < 4 ---> -1 < 4 is true
for x=7 ---> 7-1 < 4 ---> 6<4 is false
so for values x<5, the statement is true
and for values x>=5, the statement is false as expected
Andrew S.
It's only one problem using x=0 for x-1<410/26/20