What is the 5th number in the sequence. f(1)=3, when f(n)=f(n-1)-2

Answer 1

f(2) = f(1)-2 = 3-2 = 1

f(3) = f(2)-2 = 1-2 = -1

f(4) = f(3)-2 = -1-2 = -3

f(5) = f(4)-2 = -3 -2 = -5

f(6) = f(5)-2 = -5-2 = -7

f(7) = f(6)-2 = -7-2 = -9

f(8) = f(7) - 2 = -9-2 = -11

so the sequence is 3,1,-1,-3,-5,-7,-9,-11,...

the next term is 2 less than the previous term