Sevag K. answered • 02/18/15
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f(x) = x² -5x factor this function
x(x-5) = 0 ----> either x =0 , or x -5 =0 then x =5
the two values of x make f(x) =0 are 0 and 5
we can check by substituting these two values
at x = 0 ----> f(0) = 0² - 5 * 0 ---> f(x) =0
at x =5 ----> f(5)= 5² -5 * 5 ---> f(x) =0
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Sevag K.
if you subtract you would lose one of the solutions. number of roots (zeros) is equal to power of x (exponent); since u have x² then u have to have 2 zeros (2 roots).
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02/19/15
Hannah S.
02/18/15