Write an equation in standard form of the line that passes through (4,−1) and has the slope m=3

Answer 1

Write an equation in standard form of the line that passes through (4,−1) and has the slope m=3

1. Standard form is: ax + by = c (where a, b and c are constants)
2. since you are given the slope and a point; you can use y = mx + b (m is slope and b is the y intercept) and work back to get to standard form for your answer.
3. y = 3x + b (4, -1) now plug in your x and y from the coordinate given and solve for b
4. -1 = 3(4) + b; -1 = 12 + b; b = -13, plug this back into the equations above to get:
5. y = 3x - 13 but this is in slope-intercept form, so put the x on the otherside:
6. -3x + y = -13

I hope this helps you understand the process! :-)