Write an equation in slope intercept form if the line that passes through (-2,5) and (-4, -5)

Answer 1

the line has slope = (5--5)/(-2--4) = 10/2 = 5 = slope = m

now plug that and either point into the point slope form of a linear equation

y-h = m(x-k) where m=5, (k,h) = (-2,5)

y-5 = 5(x+2) that's the point slope form of the equation, which simplifies to:

y-5 = 5x + 10

y -5x = 15

It's graphically a line with slope = 5 and y-intercept = 15. It's fairly steep, upward sloping and never in the 4th quadrant.

Just plot a rough sketch on the standard x y graph and you see it all better.