Patrick B. answered 10/23/20
Math and computer tutor/teacher
P(x)=K(X+2) [(x-1)+2i][(x-1)-2i]=
K(x-2) [(x-1)^2+4]=
K(x-2) [ x^2 -2x +5]
(0,-40) means k(-2)(5)=-40
Then k=4
Answer: 4(x-2) [ x^2 -2x +5]
Kirsten M.
asked 10/23/20Find a formula for the polynomial P(x) with
with degree 3 real coefficients
zeros at x = 1 + 2 i and x = − 2
y -intercept at ( 0 , − 40 )
Patrick B. answered 10/23/20
Math and computer tutor/teacher
P(x)=K(X+2) [(x-1)+2i][(x-1)-2i]=
K(x-2) [(x-1)^2+4]=
K(x-2) [ x^2 -2x +5]
(0,-40) means k(-2)(5)=-40
Then k=4
Answer: 4(x-2) [ x^2 -2x +5]
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