For this problem, assume that you are to pick 3 cars from the motor pool, which contains 8 subcompact cars, 8 compact cars, and 5 midsize cars.

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How many ways can you pick 3 cars, forgetting about size? There are 21 cars, so there are 21! / (3! (21 - 3)!) ways to pick 3. That's 21! / (3!/18!) = 1330.

Now, in how many of those selections would they all be the same size? There are 3 ways you could do that:

1. Pick 3 subcompacts. There are 8! / (3! (8-3))! = 8! / (3!5!) = 56 way to do that.

2. Pick 3 compacts. There are the same number of compacts as subcompacts, so there are 56 ways to do this too.

3. Pick 3 midsize cares. There are 5! / (3! (5-3))! = 5! / (3!2!) = 10.

So there are a total of 56+56+10 = 122 ways to pick 3 cars that are all the same.

So subtract that from the number of ways to pick 3 cars (1330) to get the number of ways to pick 3 cars that are NOT all the same. That's 1208.

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