Math word problem

Question

Joseph invests $8300 in two different accounts. The first account paid 13%, the second account paid 3% in interests. At the end of the first year he had earned $629 in interest. How much was in each account?

Answer 1

.13x + .03(8300-x) = 629

.1x = 629 -.03(8300)

x = 380/.1 = 3800

$3,800 invested at 13%

$4,500 invested at 3%

.13(3800) +,03(4500)

= 494 + 135 = 629