Find the equation of the line parallel to x+3y=4 passing through the point (2,5)

Answer 1

Hi Laniah,

x+3y=4

y=-1/3x+4/3

The slope of the new parallel line is also -1/3.

Passing through (2,5)

y-y_1=-1/3(x-x1)

_{y-5=-1/3(x-2)}

_{y=-1/3x+2/3-5}

_{y=-1/3x-13/3 is the equation of the new parallel line.}