One leg of a right triangle is twice as long as the other leg, if the hypotensue side is 5cm long then what is the measure of the shorter leg.

Answer 1

(2s)^2 + s^2 = 5^2 = 25

5s^2 = 25

s^2 = 25/5 = 5

s = sqr5

S= about 2.2

4.4^2 + 2.2^2 = 25