Let x be the angle, then
180-x is the supplement and 90-x is the complement so that
180-x = 5(90-x)
180-x=450-5x
You should be able to finish it from here.

Paul M.
10/21/20
Lorelai W.
asked 10/20/20The measure of the supplement of an angle is five times the measure of its complement.
The measure of the angle is ____, the measure of its complement is _____, and the measure of its supplement is _____.
What do I put in the blanks? How do I figure this out?
Let x be the angle, then
180-x is the supplement and 90-x is the complement so that
180-x = 5(90-x)
180-x=450-5x
You should be able to finish it from here.
Paul M.
10/21/20
Cecilia M. answered 10/20/20
Experienced Teacher Specializing in Mathematics for ages 3 - 50+
Paul M is correct!
Another way is
C = complement of the angle in degrees
A = the unknown angle in degrees
S = supplement of the angle in degrees
Equation for five times the complement of the angle is equal to the supplement
5C + A = 180°
therefore
the complement of the angle is equal to 90 degrees minus A(unknown angle)°
C = 90° - A
Now replace 90° - A for C in the first equation.
5(90° - A) + A = 180°
Distributive (5 x 90°) - 5(A)
450° - 5A + A = 180°
Combine like terms
450° - 4A = 180°
450° - 180° - 4A + 4A = 180° - 180° + 4A
Combine like term again
270° = 4A
270°/4 = 4A/4
67.5° = A
Now fill in to find the complementary and supplementary angles.
5C + A = 180
5C + 67.5° = 180
-67.5 = -67.5‾
‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾
5C = 112.5°
5C / 5 = 112.5° / 5
C = 22.5
5C = S
5(22.5°) = S
112.5° = S
The measure of the angle is 67.5 °, the measure of its complement is 22.5°, and the measure of its supplement is 112.5°.
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Lorelai W.
Thank you!10/21/20