System 1 has no solution because the variable terms of the second equation are both the same multiple of the variable terms in the first, but the constant values do not share that relationship. Multiplying the first equarion by 4 yields 20x +4y = 52, while the second equation is 20x + 4y = 64. Subtracting the second leaves 0 = -12, which is a false statement, which means there is no solution.
The second system has infinte solutions because the equations are the same. The second is 4 times the first, and written differently, but they both can be written as 20x + 4y = 52, so they share an infinte number of common solutions for x and y.
