J.R. S. answered 10/20/20
Ph.D. University Professor with 10+ years Tutoring Experience
Write a correctly balanced equation:
2NO(g) + 02(g) ==> 2NO2(g) ... balanced equation
Next, find which reactant is limiting:
moles NO present = 33.6 g NO x 1 mol NO/30 g = 1.12 moles NO present
moles O2 present = 26.9 g O2 x 1 mol O2/32 g = 0.841 moles O2 present
Since according to the balanced eq. it takes TWO moles NO for each ONE mol O2, NO is limiting.
Next, based on the limiting reactant, calculate moles of NO2 produced:
1.12 moles NO x 2 moles NO2/2 moles NO = 1.12 moles NO2 produced
Finally, convert moles NO2 to grams NO2:
1.12 moles NO2 x 46 g/mol NO2 = 51.5 g NO2 will be produced
For part 2, use the Ideal Gas Law:
PV = nRT and solve for V (volume)
V = nRT/P = (1.12 moles)(0.0821 Latm/Kmol)(301K)/0.945 atm (change T to Kelvin and mbar to atm)
V = 29.3 L