What is an equation of the line that passes through the point (-1,-6) and is perpendicular to the line x+6y=6

Answer 1

Rewrite the equation of the given line in slope intercept format y=mx +b to find the slope

x+6y=6

6y=-x+6

y=-(1/6)x +1

slope is -1/6

slope of perpendicular would be the negative reciprocal, 6

use point slope form to find the equation of the perpendicular line

y-y1= m(x-x1) where m is slope 6, (x1,y1) =(-1,-6)

y-(-6)=6(x-(-1))

y+6=6(x+1)

y+6=6x+6

y=6x

equation of the perpendicular line would be

y=6x

Answer 2

x+6y=6

y=1-1/6x

The slope of the perpendicular line is the negative reciprocal of the given slope -1/6.

So it is 6

The equation of the perpendicular line is:

y-y_1=m(x-x1)

y-(-6)=6(x-(-1))

y=6x

y-y_1=6(X-X1)

Y-(-1)=6(X-(-6))

Y+1=6X+36

Y=6X+35 is the equation of the perpendicular line.