Equation question

Question

Write the equation of a line that passes through point (-8, 0) and is perpendicular to line 3x - 5y = 6

Answer 1

solve for y

-5y= -3x + 6

y = (3/5)x - 6/5

slope = 3/5

slope of a perpendicular line = negative inverse or -5/3

y = (-5/3)(x+8)

3y = -5x - 40

5x+ 3y = -40 is the equation of a line through (-8,0) and perpendicular to 3x-5y = 6