
Greg B. answered 10/16/20
Math Teacher and retired PhD Mechanical Engineer
4x^2+32x+64-9y^2+54x-81 = 53+64-81 = 36
4(x+4)^2-9(y-3)^2 =36
(1/9)(x+4)^2 -(1/4)(y-3)^2 = 1
(-4,3)
Dard D.
asked 10/16/20The hyperbola is given by equation
4x2 – 9y2 + 32x + 54y – 53 = 0.
Find the coordinates of the center, the foci, the eccentricity and the asymptotes of the hyperbola.
Greg B. answered 10/16/20
Math Teacher and retired PhD Mechanical Engineer
4x^2+32x+64-9y^2+54x-81 = 53+64-81 = 36
4(x+4)^2-9(y-3)^2 =36
(1/9)(x+4)^2 -(1/4)(y-3)^2 = 1
(-4,3)
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