
Greg B. answered 10/16/20
Math Teacher and retired PhD Mechanical Engineer
1) 5x -4y = 4
2) 3x -2y = 3
solve eqn2 for 2y, 3) 2y = 3x - 3
substitute 2y from eqn3 into eqn1 and solve for x
5x -2(3x -3) = 4
5x -6x + 6 = 4
x = 2
solve eqn3 for y
2y = 3(2) -3 = 3
y = 1.5
{2,1.5}