Patrick B. answered 10/15/20
Math and computer tutor/teacher
multiplies first equation by 3 so as
to clear away the fractions:
x + 6y = 12
vs
x + y = -3
subtracts: 5y = 15
y = 3 ---> x = -6
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multiplies 2nd equation by 2=6/3:
then
1/3 x + 2y = 4
6/3 x + 2y = -6
subtracts:
5/3 x = -10
x = (-10)(3/5) = -6
then (1/3)(-6) + 2y = 4
-2 + 2y = 4
2y = 6
y = 3