Logarithm Problem

Question

If log a = 3 log b - 2 log c, find an expression for a that does not involve logarithms.

Which one is it

a = 1(b/c)

a = 3b/2c

No solution

a = b^3/c^2

a = 6bc

a = b^3 * c^2

Answer 1

You need to employ your rules for logs

3log b is the same as log(b^3) and 2 log is the same as log(c^2)

Finally loga -log b is the same as Log(a/b)so this simplifies to

loga= log(b^3/c^2)

so a=(b^3/c^2)