The domain of the function g(x) is all x such that the quantity 6-x>=0. Hence, the domain of g is the interval (-\infty,6]. For the function f(x) is not clear what you mean. Is it 7/(x^2-14) or is it 7/(x^2)-14?
Nikolaos P.
tutor
Then the domain of f(x) consists of all those x such that x^2-14 is not equal to 0. Hence, domain(x)=(\infty,-sqrt(14))union(-sqrt(14),sqrt(14))union(sqrt(14),\infty).
For the domain of the product (fg) we must have that both functions are well defined for a given e. Hence the domain(fg)=domain(f) intersection domain(g)=(-\infty,-sqrt(14))union(-sqrt(14),sqrt(14))union(sqrt(14,6].
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10/14/20
Ariel Y.
It is 7 / (x²-14). 7 over x squared minus 14. Trying to find (f ·g)(x)=? and the domain of it in interval notation, sorry for the confusion10/14/20